Pi bonding, temperature volume

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• Physics: Pressure, height, and Kelvins in a gas-filled cylinder.

  Volume (V)/Temperature (T) is Constant In the first Case: Height is 0.120m Temperature is 273K Volume of a Cylinder is given by Pi*R^2*h = Pi*R^2*(0.120) So, V/T = [Pi*R^2*(0.120)]/273 --- (1) In the Second Case: Height is What we need to

• Heat and Thermodynamics: Monoatomic to diatomic

  thermal Initially, a quantity of a monatomic gas (cv=3R/2) occupies a rigid container with volume V=0.19m^3, The temperature and pressure are Ti=287k and Pi=108Kpa.

• Compute the Fermi energy and momentum at absolute zero

  We have: Vp = 4/3 pi Pf^3 where Pf is the Fermi momentum. This then yields the number of states N below the Fermi momentum as: N = 8 pi/(3 h) V Pf^3 But N is also the number of electrons if the gas is at zero temperature.

• Paramagnetic Elements

  electrons in the anti-bonding pi orb...

• Design a cylinder to compress 68 degree Farenheit air

  A = pi*r^2 + 2pi*r*l while volume = V = pi*r^2 * l therefore, for given volume V: A = pi*r^2 + 2pi*r*(V/pi*r^2) => A = pi*r^2 + 2V/r For maximum A: dA/dr = 0: => 2*pi*r - 2V/r^2 = 0 => 2pi*r = 2V/r^2 => r^3 = V/pi => r = (V/pi)^(1/3) Because

• LeChatelier's Principle and Hydrogen Bonding

  Utilizing Le chatelier's principle, indicate the shift (if any) that would occur to C2H6+heat =C2H4+H2 (explain your reasons) a if C2H6 is removed from the system b if the volume of the container is increased c if the temperature is raised 4.

• Degrees of freedom of diatomic molecule and Fermi energy

  The volume in momentum space is 4/3 pi Pf^3, so we have: N = 8 V/(3h^3) pi Pf^3 Then at zero temperature all the lowest energy states are filled, and then N will be equal to the number of molecules.

• Determining the Diameter of a Bore in a Thermometer

  rise of dt=10 C would cause the volume to increase by dV = b*dT*V0 = 0.000181/C * 10C * 0.1 meter^3 = 0.000181 m^3 This dV is the volume of a cylinder of unknown diameter D and height h = 2 cm = 0.02 m, that is dV = pi*(D^2/4)*h and

• Expansion of Pipes and Spheres Given the Coefficient of Linear Expansion

  The volume of a sphere is given by V=4/3 pi r^3 1) Linear dimensions (e.g. length, diameter) for most substances increase as the temperature increases.