Chemistry Homework Solutions
#16442
Show work-Oswald process - mass and how much oxygen required?
9) Industrially, nitric acid (HNO3) is produced by the Oswald process represented by the following - what mass of NH3 is needed to produce 5 tones of HNO3? How much Oxygen is required?
4NH3 + 5O2 = 4NO = 6H20
2NO + O2 = 2NO2
2NO2 + H2O = HNO3 + HNO2
The question is answered with easy steps and explanations.
What is this?
By OTA - Overall OTA Rating
Kishore V.C., PhD (IP) - 4.8/5
Purchase Cost Now
$2.19 CAD (was ~$7.98)
Included in Download
- Plain text response
Why you can trust BrainMass.com
- Your Information is Secure
- Best Online Academic Help Service
- Students find real academic Success
- Oswald Process: Find the Percent Yield - The first step in the Oswald process for producing nitric acid is: 4NH3(g) + 5O2(g) > 4NO(g) + 6H2O(g) If the reaction of 150 g of ammonia with 150 g of oxygen gas yields 87g of nitric oxide(NO), wh ...
- Question 62 for Solution Set from Chemistry by Zumdahl - Please see attachment for Question. NOTE: This is part of a Solution Set that covers Chapters 1-9 of "Chemistry" By Zumdahl, Sixth Edition (Houghton Mifflin). If you are interested in the other pos ...
- Chemistry Help - 1. Calculate the molarity of the following solutions from this acid-base titration data: a. If 250 ml of Ba(OH)2 of unknown concentration with a methyl red indicator present is titrated with [0.32 ...
- oxidation number method - How do you note the change in the oxidation number method with this equation C+HNO3--->CO2+NO2+H2O oxidation-C-->CO2 C+2h2O--->CO2 C+2H2O--->CO2+4H+4e- reduction=HNO3--->H2O HNO3-->H2O+2H2O H ...
- How many grams of KNO3 can be made from 591.9 g KCl and 830.0 ml of 12.0 M HNO3 by the reaction: - How many grams of KNO3 can be made from 591.9 g KCl and 830.0 ml of 12.0 M HNO3 by the reaction: KCl (s) + HNO3 (aq) ----> KNO3 (s) + Cl2 (g) + NOCl (g) +H2O (I) Also, how much of the excess re ...
