NEED TO SHOW ALL WORK on ALL 7 Questions

#1 the us navy has a system for communication with submerged submarines. the system fused radio waves with freequency of 76s -1 (small s and -1) What is the wazelength of this radiation in meters? and Miles?

#2 Green light has a wavelength of approximatelly 5.0 X 10 2 nm (small 2 power) What is the frequency of this light? What is the energy in joules of one photon of green light? what is the energy in jouls of 1.0 mol og photons of green light?

#3 to cause a cesium stom on a metal surface to lose an electron, energy of 2.0 x 10 2 kj/mol (small 2 to the power) is required. calculate the longest possible wavelength of light that can ionize a cesium atom. What is the region of the electromagnetic spectrum in which this radiation if found?

#4 Consider only the following energy levels for the hydrogen attom.
_____n=4
_____n=3
_____n=2
_____n=1
The emission spectrum of an excited H atom consists of transisions between these levels.
a) how many emmission lines are possible, connsidering only the five quantum levels
b) Photons of the lowest frequency are emitted in transision from the level with n=____ to the level with n=_____.
c) the emmission line have the shortest wavelenght corresponds to a transition from the level with n=_____ to the level with n=____
d) the emmission line have the highest energy corresponds to a transition from the level with n=_____ to the level with n=____

#5 Calculate the wavelength of light emitted when an electron change from n= 3 to n=1 in the H atom. In what region of the spectrum is this radiation found?

#6 What is the maximum number of orbitals that can be identified by each of the following sets of quantum numbers? when "none" is the correct answer, explain
a) n=4, l=3,
b) n5
c) n=2, l=2
d) n=3, l=1, ml=-1 Seconf l is small

#7 When voyager 1 encountered the planet neptune in 1989 the planet was 2.7 billion miles (2.7 x 10(9 power) miles) from earth. how long did it take for the televition picture signal to reach earth from Neptune? (1 mile + 1.61 km.)