Top of Form
Top of Form
A sample of solid monoprotic acid with molar mass equal to 192.3 g/mol
was titrated with 0.1237 M sodium hydroxide solution. Calculate the mass
in grams of acid to be used if the volume of NaOH to be used is 25 mL.
Do not enter the units. Be sure to consider significant figures. If you
wish to use scientific notation, use the "e" format - eg. 7.31e4 = 73100
& 1.90e-2 = 0.0190
Top of Form
What is the total number of non-bonding valence electrons in chlorine
nitrate, ClONO2?
(All O atoms bonded to N, Cl bonded to O)
a.
) 16
b.
) 18
c.
) 19
d.
) 20
e.
) 22
Bottom of Form
Top of Form
Which species has two lone pairs on the central atom?
a.
) BCl3
b.
) PCl3
c.
) XeF4
d.
) SF4
e.
) SF6
Bottom of Form
Top of Form
All of the following species contain only atoms with exactly full (2
electrons for H, 8 otherwise) valence shells except
a.
) CH3OH
b.
) O2
c.
) NH4+
d.
) ClO2-
e.
) BH3
Bottom of Form
Top of Form
Which of the following molecular species are best described using three
charge-minimized resonance structures? (The central atoms are
underlined)
a.
SF4
b.
SO3
c.
SO32-
d.
HSO4-
e.
SO2+
Bottom of Form
Top of Form
Which of the following statements are true regarding the Lewis
structures of N2O and NO2-?
a.
There are more than eight electrons in the valence shell of one of the
atoms in NO2-.
b.
There are positive (+) formal charges in both of these species.
c.
There are four bonds about one of the N atoms in N2O.
d.
There are negative (-) formal charges in both of these species.
e.
There are no lone pairs on either N in N2O.
Bottom of Form
Top of Form
H° for the reaction:
C2H5Cl(g) ---> HCl(g) + C2H4(g)
given the following bond energies in kJ/mol: C-C, 348; C-H, 414; C-Cl,
327; H-Cl, 431; C=C, 615
a.
) +43 kJ
b.
) -305 kJ
c.
) +109 kJ
d.
) -43 kJ
e.
) +305 kJ
Top of Form
H is the lattice energy of MgCl2(s)?
a.
) Cl2(g) + Mg(s) ---> MgCl2(s)
b.
) MgCl2(s) ---> Mg(g) + 2Cl(g)
c.
) Mg2+(g) + 2Cl-(g) --> MgCl2(s)
d.
) MgCl2(s) ---> Mg2+(aq) + 2Cl-(aq)
e.
) Mg(g) + 2Cl(g) --> Mg2+(g) + 2Cl-(g)
Top of Form
Based on ionic radii and charges which of the following solids would
have the smallest (magnitude) lattice energy?
a.
) CsBr
b.
) LiF
c.
) CaCl2
d.
) CaO
e.
) BaO
Top of Form
(g) = +844 kJ.
Enthalpy of sublimation of Ca (s) = 178 kJ.
First ionization energy of Ca (g) = 590. kJ.
Second ionization energy of Ca (g) = 1150. kJ.
Standard enthalpy of formation of CaO (s) = - 635 kJ.
Trailing zeros should be considered significant.
Do not enter your answer with scientific notation.
Bottom of Form
Chemistry Homework Solutions
#26783
Bonding and Molecule formation
A sample of solid monoprotic acid with molar mass equal to 192.3g/mol was titrated with 0.1237M sodium hydroxide solution. Calculate the mass in grams of acid to be used if the volume of NaOH to be used is 25mL.
(Stt attachment for full question)
What is this?
By OTA - Overall OTA Rating
Morris (David) Roth, MS - 4.8/5
Purchase Cost Now
$2.19 CAD (was ~$15.96)
Included in Download
- Plain text response
- Attached file(s):
- Chem.doc
Why you can trust BrainMass.com
- Your Information is Secure
- Best Online Academic Help Service
- Students find real academic Success
- Acid-Base Reactions: Names to Formulas from acid base reactions - What would be the proper balanced molecular and net ionic equations for each of these neutralization reactions? - solid chromium (III) hydroxide reacts with nitric acid - aqueous hypochlorous acid ...
- Calculate Ka for a monoprotic acid - In a 4.03 * 10-2 M solution of a monoprotic acid, the percent dissociation is 49.6. Calculate Ka for this acid.
- Calculate the pH of a weak monoprotic acid - The pH of a weak monoprotic acid (HA) is 3.75. If the ionization constant is 8.9 x 10^ -6, what is the concentration of the weak acid? a) 0.890 M b) 5.05 M c) 0.0500 M d) 0.00355 M e) 0.00712 ...
- What is the molarity of the solution? (i.e. [HA]+[A-].) - An aqueous solution of a monoprotic acid ("HA"; Ka = 3.8210-1) has a pH of 3.93. What is the molarity of the solution? (i.e. [HA]+[A-].)
- Titration - (See attached file for full problem description) --- Equation 4: pH = log [H3O+] and, pKa = log Ka Henderson-Hasselbalch equation: pH = pKa + log Equation 7 become ...
