Stoke's Law problem (3 parts)
Stokes' Law describing partial sedimentation is given by:
Rate = [(gd^2)(Δρ)]/18η
where g = 9.81 m s^-2 is gravitational acceleration. Δρ is the density difference between particles and the air, air viscosity of η = 1.67E-4 g cm^-1 s^-1 and d is the particle diameter in centimeters.
a. Calculate the weight(g) of one cubic centimeter of air at 1.0 atm and 15 degrees celsius.
b. Assume particles have a density of 2.45 g cm^-3 and are being released by a 100 m smokestack. How long does it take (s) a 25μm particle to settle to the ground?
c. It rains exactly once a week. What is the smallest particle size (μm) that can settle to the grounds before wet removal?
Solution to problem involving sedimentation/settling rates of airborne particles as per Stoke's Law.
- Plain text response
- Your Information is Secure
- Best Online Academic Help Service
- Students find real academic Success
- How many grams of particulates does a person breathe in per day? - If a person breathes in 20m3 of air per day and the air contains 263 micro grams of particulates per m3, how many grams of particulates does a person breathe in per day?
- How many grams of particulates? - If a person breathes in 20m3 of air per day and the air contains 263 micrograms of particulates per m3, does a person breathe in per day?
- Stokes Law and particle sedimentation - Stokes' Law describing partial sedimentation is given by: Rate = [(gd^2)(Δρ)]/18η where g = 9.81 m s^-2 is gravitational acceleration. Δρ is the density difference between ...
- chemistry word problem - •If a person breathes in 20m3 of air per day and the air contains 263 micrograms of particulates per m3, how many grams of particulates does a person breathe in per day? Question also in attachme ...
- Particulates breathed in per day - If a person breathes in 20m^3 of air per day and the air contains 263 micrograms of particulates per m^3, how many grams of particulates does a person breathe in per day?
