Info:
BOD: Biochemical Oxygen Demand
BOD5 is the total amount of oxygen consumed by microorganisms during
the first five days of biodegradation
BOD5 = (DOi – Dof)/(P) this is the five-day BOD of a diluted sample
Where DOi = the initial dissolved oxygen (DO) of the diluted wastewater
DOf = the final DO of the diluted wastewater, 5 days later
P = the dilution fraction = (volume of
wastewater)/(volume of wastewater plus dilution water)
A standard BOD bottle holds 300 mL, so P is just the volume of
wastewater divided by 300 mL
5.12)
Some wastewater has a BOD5 of 150 mg/L at 20 degrees Centigrade. The
reaction rate k at that temperature has been determined to be 0.23/day.
Find the ultimate carbonaceous BOD
Find the reaction rate coefficient at 15 degrees Centigrade
Find BOD5 at 15 degrees Centigrade
Chemistry Homework Solutions
#86790
Assistance with finding the ultimate carbonaceous BOD, reaction rate coefficient, and BOD5 at 15 degrees Centigrade given a BOD5 of 150 mg/L at 20 degrees Centigrade and reaction rate k at that temperature of 0.23/day.
Info:
BOD: Biochemical Oxygen Demand
BOD5 is the total amount of oxygen consumed by microorganisms during the first five days of biodegradation
BOD5 = (DOi – Dof)/(P) this is the five-day BOD of a diluted sample
Where DOi = the initial dissolved oxygen (DO) of the diluted wastewater
DOf = the final DO of the diluted wastewater, 5 days later
P = the dilution fraction = (volume of wastewater)/(volume of wastewater plus dilution water)
A standard BOD bottle holds 300 mL, so P is just the volume of wastewater divided by 300 mL
5.12)
Some wastewater has a BOD5 of 150 mg/L at 20 degrees Centigrade. The reaction rate k at that temperature has been determined to be 0.23/day.
a) Find the ultimate carbonaceous BOD
b) Find the reaction rate coefficient at 15 degrees Centigrade
c) Find BOD5 at 15 degrees Centigrade
Assistance with finding the ultimate carbonaceous BOD, reaction rate coefficient, and BOD5 at 15 degrees Centigrade given a BOD5 of 150 mg/L at 20 degrees Centigrade and reaction rate k at that temperature of 0.23/day.
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