1) Calculate the pH of the following solutions:
(a) 0.010 M acetic acid (Ka= 1.76E-5)
CH3COOH + H2O --> H3O+ + CH3COO-
initial 0.010 -- ? ?
Equilibrium 0.010-x -- ? ?
Show how did you solve this equation to get 1.76E-5:
Ka = [H3O][CH3COO]/[CH3COOH] = 1.76E-5
(b) 0.010 M hydrochloric acid
(c) Which acid solution in Question#1(a) or #1(b) has the lower pH ?
(d) Why does the acid solution noted in (c) have a lower pH ?