Chemistry Homework Solutions
#26161
Equilibrium constant of a reaction in a sealed tube
Ethanol and Ethanoic acid react to form Ethyl ethanoate and water according to the equation
C2H5OH + CH3COOH = CH3COOC2H5+H2O
When two moles each of ethanol and ethanoic acid are allowed to react at 100 degrees celcius in a sealed tube, equilibrium is established when two-thirds of a mole of each of the reactants remains. Calculate the equilibrium constant for this reaction.
= is actually two arrows pointing opposite directions
This solution looks at the equilibrium constant for a reaction.
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