The balanced equation: C3 H8 + 5 O2 ---> 3 CO2 + 4 H20. If 0.3818 mols of C3 H8 and 1.718 mols of O2 are allowed to react (this is the only reaction), theoretrically how many mols of water should be produced?
My answer was 1.1454
I took 0.3818 mol C3 H8 and multiplied by 3 CO2/1 mol C3 H8
This obviously is incorrect.