I recently did an experiment where the addition of bromine to trans-cinnamic acid gives a dibromide with two stereocenters (chiral centers). Thus, there were four stereoisomers possible (see figures on page 136 on attachment).
According to the melting points of my product, I ended up with the racemic mixture (2R,3S) and (2S,3R), erythro diastereomer (see attachment). EVERYTHING I have read points to the idea that this should be an anti addition, but the teaching assistant has just told me, no, this is a syn addition since we have ended up with the erythro diastereomer. How can this be? All the literature says that when a bromonium ion is formed in the bromination of an alkene, this is anti addition.
(1) Showing a lot of detail, please draw out the mechanism of the reaction of bromine with trans-cinnamic acid step-by-step for me. How does each bromine enter?
(2) Is it syn or anti addition or both?
(3) Isn't the erythro diastereomer a meso compound?