view attachment
view attachment
view attachment
In a murder investigation, the crime scene investigators arrive 5am to examine the body. They found the body temperature to be 30 degrees celcius in a constant room temperature of 20 degrees celcius. (Normal body temperature is taken to be 37 degrees celcius). At 5.30 am the coroner arrived and measured the body temperature to ...continues
Limits using taylor series and macluarin
Attached are 3 images of my 11 problems.
Approx. the deriv. of y=x^3 at x=2 by assuming delta x = 0.001 and determining the corresponding change delta y. Compare the approximate value with the ecaxt value. This is what I did - does it look at all right? y(2)=(2)^3=8 y(2.01)=(2.01)^3=8.120601 delta y=8.120601-8=0.120601 dy/dx~delta y/delta x = 0.120601/0.001 ...continues
Solve the following two equations. In each case, determine dy/dx: a.)y=xcos(2x^2) Is this right? y'=x(-sin)(2x^2)(4x) =-4x^2sin(2x^2) b.)y=xe^-x^2 Is this right? y'=-xe^-x^2+1(e^-x) =-xe^-x^2+e^-x
How do you find the derivatives of: ln(1 + 5/x) and of: (ln(1 + x)/x) / (1/x) ?
Test for convergence or divergence, absolute or conditional. If the series converges and it is possible to find the sum, do so.
Find the open interval of convergence and test the endpoints for absolute and conditional convergence.