1. Consider the simplex tableau
x y u v w M
[ 1 0 3 0 0 0 | 10]
[ 0 0 1 0 1 0 | 0]
[ 0 1 -6 0 0 0 | 3]
[ 0 0 8 1 0 0 | 7]
[ 0 0 5 0 0 1 4]
The tableau above is the final one in a problem to minimize –x + 2y.
The minimum value of –x + 2y is:
-10
-4
0
4
none of the above
2. The inequality 2x – y + 5z (greater than or equal to symbol) -6 is
equivalent to the inequality
2x – y + 5z (less than or equal to symbol) -6
2x – y + 5z (greater than or equal to symbol) 6
-2x + y – 5z (less than or equal to symbol) -6
-2x + y -5z (greater than or equal to symbol) 6
none of the above
Consider the following linear programming problem: A workshop of
Peter’s Potters makes vases and pitchers. Profit on a vase is $3;
profit on a pitcher is $4. Each vase requires Ð… hour of labor, each
pitcher requires 1 hour of labor. Each item requires 1 unit of time in
the kiln. Labor is limited to 4 hours per day and kiln time is limited
to 6 units per day. Initial and final tableaux are shown in finding
the production plan which will maximize profits: (x = number of vases
and y = number of pitchers made per day).
x y u v M
[ -1 1 1 0 0 | 4 ]
[ 2 | ]
[ 1 1 0 1 0 | 6 ]
[-3 -4 0 0 1 | 0 ]
(initial)
x y u v M
[ 0 1 2 -1 0 | 2 ]
[ 1 0 -2 2 0 | 4 ]
[0 0 2 2 1 | 20 ]
(final)
If kiln time were decreased by one unit per day, determine the optimal
performance schedule.
x = 3, y = 4
x = 4, y = 2
x = 6, y = 1
x = 2, y = 3
none of the above
In a linear programming problem in a standard from, the initial and
final tableaux are given as below:
x y u v M
[ 1 3 1 0 0 | 50 ]
[ 1 5 0 1 0 | 70 ]
[-6 -24 0 0 1 | 0 ]
(initial)
x y u v M
[ 0 1 2 -5 -3 | 20 ]
2 2
-1 1
[ 1 0 2 2 0 | 10 ]
[0 0 3 3 1 | 360]
(final)
Given that x (greater than or equal to sign) 0 and y (greater than or
equal to sign) 0, if h units were added to the first resource, the
maximum value of the objective function is
360
360 + 3h
360 + h
360 + h(to the 5th power)/2
none of the above
5. To solve the linear programming problem
Minimize 50x + 70y subject to:
x + y (greater than or equal to symbol) 6
3x + 5y (greater than or equal to symbol) 24 we can use the simplex
method on its dual.
x (greater than or equal to symbol) 0 , y (greater than or equal to
symbol) 0
The objective function of the dual is
u + 3v
u + 5v
6u + 24v
70u + 50v
none of the above
