(See attached file for full problem description)
Find the fourier transform of x^k, where k is a positive integer and x is a single reaal variable.
Applications of Fourier transform
Define a Fourier Transform. What are its properties and application areas ? Describe its application in signal processing.
(See attached file for full problem description) Consider a periodic function f(x) with period L. Over one period, f(x) = sin(2*pi*x/L) over the interval –L/4 to L/4, f(x) = 0 over the intervals –L/2 to –L/4, and L/4 to L/2. Derive an expression for the nth Fourier series coefficient, an. In the Fourier series expansion ...continues
Find the inverse Fourier transform of each of the following Fourier transforms: X(w) = cos(2w) X(x) = jw
Find the inverse Fourier transform of each of the following Fourier transforms: X(x) = jw The answer I have is x[n] = (-1)^n / n (for n not equal to zero) 0 (for n = 0) I dont know how to get this
Using Fourier transforms where possible, derive the Fourier transforms of the following functions using the relationship: F(fx) = ∫ f(x)*exp[-i2πfxx]dx a.) f(x) = δ(x-a) b.) f(x) = cos(x-ø) c.) f(x) = αsin(ax)
Using Fourier transforms where possible, derive the Fourier transforms of the following functions using the relationship: a.) f(x) = exp[i2po(x/lamda)sin(theta)] b.) f(x) = exp(- /ax/ ) See the attached file for full description.
Discrete Time Fourier Transform with Matlab
Please see the attached file for full description. Calculate by hand the X(omega), DTFT of the sequence x[n]=[1 1 1 1 0 0 0 0] for n=0:7, zero else. Using Matlab, plot the real and imaginary components of your result for X(omega) for omega=0:0.01:2*pi, one plot for the real, one part for the imaginary. On the same plot ...continues
(See attached file for full problem description) For sequence x[n]=[1 1 1 1 0 0 0 0] for n=0:7, so N=8 Using above x[n]: a) stem(x); b) Use the shift theorm to plot x delayed by 1, 4, 5, 6, and 8 samples, and plot the result for each. Remember the shift theorem says a delay by t0 seconds is equal to multiplying the spe ...continues
