(hint use the
Division Algorithm and Binomial Theorem)
be relatively prime. Prove that if a is primitive root modulo mn, then
a is primitive root modulo both m and n
is not congruent to
(p-1), then m is a primitive root modulo p
a. Let =2 +1 (2 (Power 2(power n))) Plus 1. Prove that P is a prime Dividing , then the smallest m such that P (2 -1) is m = 2 (hint use the
Division Algorithm and Binomial Theorem)
Please see attached.
There are a variety of proofs in this solution regarding modular arithmetic.