Prove a mapping is a normal subgroup
Given a problem like this... Let @:G-->H be a homomorphism of G onto H, and let N be a normal subgroup of G. Show that @(N) is a normal subgroup of H. How do I prove that a mapping is a normal subgroup of a group? What I am missing here is some understanding of the terminology and some clear understanding of mappin ...continues
Explain what the index of a subgroup and a coset of a group are. Also, prove that if N is a subgroup of a group G such that [G: N] = 2, and if "a" and "b" are elements of G, then the product "ab" is an element of N if and only if either (1) both "a" and "b" are elements of N or (2) neither "a" nor "b" is an element of N.
Show that conjugacy of group elements is an equivalence relation.
What are the conjugacy classes in S_3?
Equivalence relations, surjective maps, partitions and fibers??
Consider any surjective map f from a set X onto another set Y. We can define a relation on X by x_1 ~ x_2 if f(x_1) = f(x_2). Check that this is an equivalence relation. Show that the associated partition of X is the partition into "fibers" f^(-1) (y) for y in Y. I would like to understand what this question is asking me a ...continues
RINGS - prove:(1)multiplicative identity is unique, (2)left & right multiplicative inverses are =
I need to understand how to show/prove the following regarding a ring R: 1) if a ring R has a multiplicative identity, then the multiplicative identity is unique. 2) if an element r that is in the ring R has a left multiplicative inverse r' and a right multiplicative inverse r", then r' = r".
Show that a set of matrices is a ring without identity element
I am given the set of infinite-by-infinite matrices with real entries that have only finitely many nonzero entries. Also, the matrix has entries a_ij, where i and j are natural numbers and there is a natural number n such that a_ij = 0 if i >= n or j >= n. I need to understand how to show that this set of matrices is a ring w ...continues
Show that a ring isomorphism has a multiplicative identity and is commutative
Suppose φ:R --> S is a ring isomorphism. Show that R has a multiplicative identity if, and only if, S has a multiplicative identity. Show that R is commutative if, and only if, S is commutative.
Show that the set of real rational functions is a field.
NOTE: In this description, R represents the symbol for the set of real numbers. I couldn't find a way to type or copy the correct R symbol for the set of real numbers. Also, the parentheses in R(x) is used to distinguish the ring R(x) of rational functions from the ring R[x] of polynomials. Show that the set R(x) of rational ...continues
Show that if R is a ring with identity element and x is an element in R, then Rx = {rx: r in R} is the principal left ideal generated by x. Similarly, xR = {xr: r in R} is the principal right ideal generated by x.