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#98694

Real Analysis Let f be continuous on the interval [0,2pi] ---> the reals and such that f(0)=f(2pi). Prove that there exists a point c in this interval such that f(c)=f(c + pi).

Let f be continuous on the interval [0,2pi] ---> the reals and such that f(0)=f(2pi).  Prove that there exists a point c in this interval such that f(c)=f(c + pi).

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Analysis1.doc
Let f be continuous on the interval [0, 2π] to the real numbers and
such that f(0) = f(2 π). Prove that there exists a point c in this
interval such that f(c) = f(c + π).

Solution Summary

Continuity and intervals are investigated. The solution is detailed and well presented. The response received a rating of "5/5" from the student who originally posted the question.

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Yupei Xiong, PhD - 4.8/5
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