BC’s U(0,t)=0
U(1,t)= 0
IC’s U(x,0)= 2sin(2(x)
Ut(x,0)= 0
Mathematics Homework Solutions
#127759
PDE
PDE Utt = Uxx+sin(3x) 0
BC's U(0,t)=0
U(1,t)= 0
IC's U(x,0)= 2sin(2x)
Ut(x,0)= 0
This provides an example of solving a partial differential equation.
What is this?
By OTA - Overall OTA Rating
Yinon Shafrir, PhD - 5/5
Purchase Cost Now
$2.19 CAD (was ~$27.93)
Included in Download
- Plain text response
- Attached file(s):
- BM 127759.pdf
- BM 127759.doc
Why you can trust BrainMass.com
- Your Information is Secure
- Best Online Academic Help Service
- Students find real academic Success
- Partial Differential Equation : Diffusion Equation and Explicit Series Solution - Consider the diffusion equation ut = ku.xx for 0 < < pi and t > 0 with the boundary conditions ux(0, t) = 0 and u(pi, t) = 0 and the initial condition u(x,0) = 1. (a) Find the separated solution ...
- Differential Equations. - 1) consider the equation (non-homogenous): Please see attachment for equation. • find its general solution • find the particular solution of this equation, satisfying the initial condi ...
- Differential Equations : Uniqueness Theorem and Initial Conditions - Using uniqueness theorem, what can you conclude about the solution to the equation with the given inital conditions? dy/dt = f(y) y1(t) = 4 for all t is a solution y2(t) = 2 for all t is a solu ...
- Particular Solution to a Differential Equation - Find the particular solution of the differential equation subject to the given conditions. See attached file for full problem description.
- Solving a differential equation with initial condition. - A relation between a function f(x) and its derivative f'(x) = x√f(x) is given with an initial condition on f(x) as f(4)=16. One needs to find the value of the second derivative of the function ...
