(See attached file for full problem description) --- Use the following table to solve 3 and 4. J0(x) J1(x) Y0(x) Y1(x) 2.4048 0.0000 0.8936 2.1971 5.5201 3.8317 3.9577 5.4297 8.6537 7.0156 7.0861 8.5960 11.7915 10.1735 10.2223 11.7492 14.9309 13.3237 13.3611 14.8974 3. Find the first four α i ...continues
(See attached file for full problem description) --- 8. The first three Legendre polynomials are P0(x) = 1, P1(x) = x, and P2(x) = 1/2(3x2- 1). If x = cosθ , then P0( cosθ ) = 1 and P1( cosθ ) = cos θ . Show that P2( cosθ ) = 1/4( 3cos2θ + 1 ). 9. Use the results of problem 8, to fi ...continues
Stochastic Differential Equations.
(See attached file for full problem description)
Please derive the TWO Dimensional wave equation. Note: derive this equation in such a way a beginner in PDE will understand. (put comment and or explain where needed)
Stochastic DE (density function,E(x).
I know this problem is very easy, finding E(x) from the distribution function. I tried to do it by integration by parts, one way I took x to be my first function and the whole exp term to be my 2nd function, but it didn't work, then I split the exponential term to 2 terms combined one with x as my first function and took the sec ...continues
Cauchy partial differential equation
prove d/dt(u(x(t),t))+tanh(x(t))(d/dx(u(x(t),t)))=0 u(x(t),0)=a(x(t)) limit as x tends to infinity of u(x,t)=0 has at most one solution.Explain why there is no boundary condition at x=0 and find a solution for the special case a(x(t))=sinh(x(t))
The meteorologists at the National Interagency Fire Center had pizza delivered to their operations center. Their lunch consisted of pizza, milk and gelatin. One slice of cheese pizza contains 290 calories, 15g of protein, 9g of fat, and 39g of carbohydrates. One-half cup of gelatin dessert contains 70 calories, 2g of protein, 0g ...continues
Please see the attached file.
Please help solve this seperable equation and a possible suggestion on how to look for factors to multiply by in order to make it exact. 8*cos^2(y)dx+csc^2(x)dy=0
y'=ty^3 with y(0)= -1 over [-3/4, 3/4] Having trouble solving for y