Physics Homework Solutions
Problem
#11350

Diode Current Manipulation - A schottky diode and a pn junction diode have cross sectional areas a=10^-4. The reverse saturation current density of the pn junction diode is 3x10^-8 A/cm^2. The reverse saturation current density of the pn junction diode is 3x10^-12A/cm^2. Determine the forward bias voltage in each diode required to yeild diode currents of 1mA.

A schottky diode and a pn junction diode have cross sectional areas a=10^-4.   The reverse saturation current density of the pn junction diode is 3x10^-8 A/cm^2.  The reverse saturation current density of the pn junction diode is 3x10^-12A/cm^2.  Determine the forward bias voltage in each diode required to yeild diode currents of 1mA.

If I use Jst=A*T^2*exp( (-q*phi|bn) / KT) to find the voltage for the Schottky diode, how do I find phi|bn from the given information?

IF I use J=q*Dn*npo/Ln+q*Dp*pno/Lp. How do I determine Ln, Lp, npo, pno, Dn, and Dp from the given information?

Thank you.


Solution Summary

A schottky diode and a pn junction diode have cross sectional areas a=10^-4.   The reverse saturation current density of the pn junction diode is 3x10^-8 A/cm^2.  The reverse saturation current density of the pn junction diode is 3x10^-12A/cm^2.  Determine the forward bias voltage in each diode required to yeild diode currents of 1mA.

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