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Initial value - find the solution to initial-value problem
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Find the solution to initial-value problem:
(x^2+1)y'= xe^y with initial condition y(0)= -1.
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Full solution is provided to the initial-value problem provided.
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(x^2 + 1) y' = x e^y
(x^2 + 1) dy = x e^y dx
dy/ e^y = x dx /(x^2 + 1)
e^-y dy = x dx ...
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