Power and Resistance

Related BrainMass Solutions

• Lightbulb resistance and efficiency

  32994 Lightbulb resistance and efficiency A GE Softwhite lightbulb is rated as follows: rated power = 60 W ; rated optical power = 820 lumens (lm) 1 lm = 1/680 W operating life = 1.5 h rated operating voltage = 115 V The resistance of the

• Transformer and Power Transfer

  The concept of maximum power transfer is to match the source resistance and the load resistance. In this condition, the load receives the highest possible power transmitted by the source.

• Electricity Resistance Voltage

  Again, the power dissipated on a resistor is: (4.1) Then: (4.2) Where are the power and resistance of the 100W bulb. are the power and resistance of the unknown bulb. We know that , therefore: (4.3) Then   5.

• Lightbulbs in a series/parallel

  116621 Lightbulbs in a series/parallel (See attached file for full problem description) (see attachment for complete solution and diagram) a) Three bulbs in series : Power dissipated in a resistance is given by the following expression :

• An amplifier with a voltage gain of +30db

  Power is the product of voltage and current, and is also defined as the square of the current times the circuit resistance, or the square of the voltage divided by the circuit resistance.

• Regulation of power supply & Gains of CE amplifier

  Input resistance] = Beta(AC)^2 x Resistance gain = 13.33^2 x 50000/1000 = 8885 A step by step solution is provided for a problem with regards to the regulation of power supply and gains of CE amplifier.

• The DC input power, heat generation and maximum thermal resistance of class A and B amplifiers are calculated, and the resulting numbers indicate that a Class A amplifier is an enormous power waster in comparison to a class B amplifier.

  563483 eat generation and maximum thermal resistance of class A and B The DC input power, heat generation and maximum thermal resistance of class A and B amplifiers are calculated.

• Current Through Series of Resistors

  2) Find the current in through 1.60, 2.50, and 5.00ohms resistors. 3) Find the total current through the battery. 4) Find the power dissipated in 1.60, 2.50, and 5.00ohms resistors 5) Which resistor dissipates the most power: the one with

• power dissipation

  P is the power iin watts, dissipated due to the resistance, most of the times in the form of heat. You can calculate how the power dissipation varies with current and/or resistance here [1].

• AC Circuits - Transformers

  When the primary voltage is 400V and it is connected to a resistive load its secondary current is 100A. (i) Calculate the required value of source resistance of the supply to give maximum power transfer.