Disodium edetate
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5. 0.1060g of sodium carbonate, dissolved in 20ml of water, was expected to give a titre of approximately 20ml of hydrochloric acid. what would you expect the approximate titre value to be if the carbonate had been dissolved in 40ml of water?
6. 20ml of a 1.103% w/v calcium lactate solution was analysed by titration against disodium edetate. Calculate the number of moles of calcium lactate in the 20ml sample.
7.20.0ml of an approximately 1%w/v calcium lactate solution titrated against 18.12ml of 0.0502M disodium edetate solution. Calculate the mass of calcium lactate in the 20.0ml sample
8. 20.0ml of a 1.011%w/v calcium lactate solution titrated against 18.34ml of 0.0503M disodium edetate solution. Calculate the molecular mass of calcium lactate
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Solution Summary
The solution tackles 3 chemistry questions on sodium carbonate and calcium lactate solution.
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. 0.1060g of sodium carbonate, dissolved in 20ml of water, was expected to give a titre of approximately 20ml of hydrochloric acid. what would you expect the approximate titre value to be if the carbonate had been dissolved in 40ml of water?
Solution
Normality N= Mass of substance/ equivalent wtx1000
If we are making 20ml of the solution, then the above factor should be multiplied by 1000/20
Then Normality of the solution becomes N= .1060/53x1000/20 =0.1 (equation 1)
The normality of sodium carbonate N1= 0.1
Assume the normality of HCl N2 = 0.1
Volume of HCl used V2 = 20 ml
Volume sodium carbonate can be calculated using the relation N1V1=N2V2
V1=N2V2/N1
V1 ...
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