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equilibrium constant Ke
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Find the value of Ke for the reaction,
A(g) + 2B (g) ---> 2C(g) + D(g)
In which it was found that at equilibrium, [A] = 0.200 mol/L, [B] = 0.200 mol/L, [C] = 0.0500 mol/L, and [D] = 0.0750 mol/L.
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This solution helps demonstrate how to calculate the equilibrium constant Ke of the reaction.
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