Kc and Kp of Reverse Reaction
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The equilibrium constant Kc for the reaction shown below is 3.8 x 10-5 at 727°C.
I2(g) = 2 I(g)
Calculate Kc and Kp for the following equilibrium at the same temperature.
2 I(g)= I2(g)
Since they give us first rxn Kc do I first take the inverse (to get the Kc for the second rxn)and then figure the Kp? Is this right? Can you show me?
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Solution Summary
This solution explains how to calculate Kc and Kp of a reverse reaction in equilibrium.
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