Parallel RL Circuit

Related BrainMass Solutions

• Superposition Theorem

  i) when v2 is shorted, RL will be in parallel with R2 and these two intern will be in series with R1 ii) when v1 is shorted, RL will be in parallel with R1 and these two intern will be in series with R2 VoRL = V1 RL/ (R2 + RL) + V2 RL/

• Thevenin's theorem, Norton's theorem circuits, networks

  ii) V th = Open circuit voltage at terminal AB is = rL * ( V)/ (rL + r2) = 10k * 10/ (10+ 2.2)k=8.196V. iii) I nor = Open circuit current at terminal AB is = V/r (Norton) = 10/1.42k = 7.2 mA. Please see the attached file.

• An RL Circuit with Switches at T=0 Switch S1 Opens

  19655 An RL Circuit with Switches at T=0 Switch S1 Opens An RL circuit with switches is shown in the figure. Switch s1 remains closed and s2 remains open for a long time (steady-state). At t=0 switch s1 opens and s2 closes. Find V_1(t) for t > 0.

• Resistors: Explanations and Calculations

  Find the equivalent resistance of all the four in parallel. Formula: 1/Rl = 1/R1 + 1/R2 + 1/R3 + 1/R4 1/Rl = 1/1.992E6 + 1/3248 + 1/13200 + 1/0.247E6 Rl = 2576 Ohms. Now if Vl = 5V, R = Rl*[(12/5)-1] = 1.4*Rl R = 1.4*2576 = 3607 Ohms.

• Potential divider and its Thevenin's circuit.

  (b) Determine Thevenin's circuit for the circuit of (a) (a) The potential divider supply circuit is shown in the diagram. For any load RL connected parallel to R2 the current and hence the voltage across R2 will decrease.

• AC/DC Current Sources Required

  1592 t + 0º ) is applied to a series RL circuit with R = 1000 ? and L = 0.1 H, what is the magnitude of the total circuit impedance? How many 100 mA current sources must be connected in parallel to produce a total current output of 300 mA?

• Superposition Theorem - Independent Sources

  Total Series Impedance Z = (R1||RL) + (R3||R4) + R2, where || means Parallel Hence V = Vs * [ (R3||R4)/ Z ] = Vc ---(1) b) Short the Voltage source Vs Total Impedance left of the Current Sources Zleft = [ (R1||RL) + R2 ] || R3 Using potential

• Time constant for a circuit

  The equivalent resistance is In the RL circuit, the time constant is So the time constant is 3.33 miliseconds. It shows how to find the time constant of the circuit. The solution is detailed and well presented.

• RL Circuits: Growth and decay of current in inductor

  72178 RL Circuits: Growth and decay of current in inductor See attached circuit. Note current source is 2A,Resistors are 2 Ohms, Inductor 2H. Assume that the switch has been open for a long time and that it closes at t=0 sec.