Calculus Test - 10 Basic Problems
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I need the full calculations as well as the answers. If I can see how you got from A to B to C I can figure it out, just the answers wouldn't help.10 basic problems.
Find the First Derivative
K(x)= 1/ (x^4)-(x^2)+1
G(t)= square root of 6t+5
G(x)= 6/[(3x^2)-1]^4
F(r)=[(r^2)-(r^-2)]^-2
Find the Limit
lim x^2/sinx
x->0
lim [(x^2)+sin^2x]/4x^2
x->0
Find the First Derivative
G(r)= square root of t+cos^2r
F(x)=sin^2(4x^3)
H(t)=(1+sin3t)^3
F(x)=x^2cot2x
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The expert examines multiple derivatives and trigonometry functions. Complete, Neat and Step-by-step Solutions are provided in the attached file.
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Find the First Derivative
K(x)= 1/ (x^4)-(x^2)+1
K(x) = 1/(x^4 - x^2 + 1) = (x^4 - x^2 + 1)^-1
Let x^4 - x^2 + 1 = u
K(u) = u^-1
dK/du = -u^-2
du/dx = 4x^3 - 2x
dK/dx = dK/du * du/dx = u^-2 * (4x^3 - 2x) = 2x(2x^2 - 1)/(u^2) = 2x(2x^2 - 1)/ (x^4 - x^2 + 1)^2
G(t)= square root of 6t+5
G(t) = Ö(6t + 5)
Let 6t + 5 = u
G(u) = Öu
dG/du = 1/2Öu
du/dt = 6
dG/dt = dG/du * du/dt = (1/2Öu)6 = 3/Öu = 3/Ö(6t + 5)
G(x)= 6/[(3x^2)-1]^4
G(x) = 6(3x^2 - 1)^-4
Let 3x^2 - 1 = u
G(u) = 6u^-4
dG/du = 6(-4) u^-5 = -24/(u^5)
du/dx = 6x
dG/dx = ...
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