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You had "2^(2/3) = 4^(1/3) = cube root of (4)"
However, if we had a case where we had a perfect square or perfect cube, could we have take the denominator root first? Why? Hi there,
Here is my explanation:
If we have a perfect cube, we could take the denominator root first.
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Perfect square/cube/fifth power
Find the smallest positive integer N such that N/2 is a perfect square, N/3 is a perfect cube and N/5 is a perfect fifth power.
If N/2 is a perfect square, N/3 is a perfect cube and N/5, it means that N=2i2=3j3=5k5 , be such a number.
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Primes and divisibility word problem
The smallest number (other than one) that is a perfect square, a perfect cube, and a perfect fifth power is calculated.
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Simplify and Reduce the Expression
22745 Simplify / Reduce the Expression (Radicals) Simplify the following expression: (see attachment)
Hint:
The first step is to make the radical a perfect cube (so that exponent equals index) so as to eliminate the radical from the denominator.
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Finding the Dimensions (Side) of a Cube Given Volume
50434 Finding the Dimensions (Side) of a Cube Given Volume A homemade loaf of bread turns out to be a perfect cube. Five slices of bread, each 0.6 in. thick, are cut from one end of the loaf.
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Important information about rational and radical expressions
Cube root of an integer.
13. Solving an equation with exponent using the even-root property
15. Solve the following equation by using the quadratic formula:
Hello
Please find the solution in the attached file.
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Solving a third degree equation
roots we choose for A fixes the cube root for B.
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Cube in water
Thus: volume of cube * density of the cube > volume of cube * density of water. Factoring out the common factor (volume of cube) we get: density of the cube > density of water.
A) The buoyant force on the cube is less than its own weight.
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C++ Programming (User Defined Functions)
a. value = cube (num1, 15.0, num3);
b. cout << cube(num1, num3, mum2);
c. cout << cube(6.0, 8.0, 10.5);
d. cout << cube(num1, num3);
e. value = cube(num1, int2, num3);
f. value = cube(7, 8, 9);
g. value = cube(int1, int2, int3); 3.