Ordinary Differential Equations and Initial-Value Problems : Unique Solution
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Find the unique solution satisfying initial conditions y(1)=0 and y'(1)=1 for
ty''-(t+2)y'=2y=0, t not equal to 0
Solve t^2y''+3ty'+5y=0
Solve the initial value problem.
y''-2y'+y=2e^t+3
y(0)=4 and y'(0)=3
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Solution Summary
The expert examines ordinary differential equations and initial-value problems. The initial conditions for satisfying solutions are provided.
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ty''-(t+2)y'+2y=0
=>t(y''-y')=2(y'-y)
Let x=y'-y
=>tx'=2x
=>x=y'-y=a t^2 ...
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