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7.8 Consider a region of space divided by a plane. The potential energy of a particle in region 01 is U1 and in region 02 it is U2.

If a particle of mass m and with speed v1 in region 01 passes from region 01 to region 02 such that its path in region 01 makes an angle theta1 with the normal to the plane of separation and an angle theta2 with the normal when in region 02.
Show that:
Sin(theta1)/sin(theta2) = 1 + sqrt[(U1-U2)/T1]
Where T1 =1/2mv^2
What is the optical analog of this problem?

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If finds the optical analog of a particle passing through two different potential regions. The solution is detailed and was rated '5/5' by the student who originally posted the questions.

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