Purchase Solution

Coulomb's Law - 2 small charged spheres

Not what you're looking for?

Ask Custom Question

2 small spheres with mass m = 15.1 g are hung by silk threads of length L = 1.21 m from a common point. When the spheres are given equal charges, so that q_1 = q_2 = q, each thread hangs at an angle theta = 26 degrees from the vertical. Find the magnitude q.

Use 9.81 m/s^2 as the acceleration due to gravity and 8.85 * 10^-12 C^2/Nm^2 as the permittivity of free space.

Purchase this Solution
Solution Summary

The solution calculates the magnitude of charges of two balls hanging from non-conducting threads.

Solution Preview

Dear Student,

Please see the solution to your problem in the attached word file
'Solution_Proof_TinyChargedSpheres_02.doc'.

Its a very simple problem. I have given one additional case, where ...

Purchase this Solution
Free BrainMass Quizzes
Classical Mechanics

This quiz is designed to test and improve your knowledge on Classical Mechanics.

Introduction to Nanotechnology/Nanomaterials

This quiz is for any area of science. Test yourself to see what knowledge of nanotechnology you have. This content will also make you familiar with basic concepts of nanotechnology.

The Moon

Test your knowledge of moon phases and movement.

Intro to the Physics Waves

Some short-answer questions involving the basic vocabulary of string, sound, and water waves.

Basic Physics

This quiz will test your knowledge about basic Physics.

View More Free Quizzes
Related BrainMass Solutions

  • electric force between two small charged spheres

    The solution shows how to apply Coulomb's law to calculate the force of repulsion between two charged spheres.

  • electric force between to two charged spheres

    F2 is the electric force on charge 1 by charge 2. By Coulomb's law, By what factor is the electric force on a sphere larger than its weight? So the electric force is 2.1 times of the weight.

  • Acceleration and Velocity of Spheres at Different Points

    97135 Acceleration and Velocity of Spheres at Different Points Three small spheres with charge 2.00 mC are arranged in a line, with sphere 2 in the middle. Adjacent spheres are initially 8.0 cm apart.

  • Coulomb's Law: Force Between Two Points

    41660 Coulomb's Law: Force Between Two Points The force between two point charges is given by F = (k(q_1)(q_2))/r^2 k = 9.0 * 10^9 * (N * M)/C^2 Using Coulomb's Law, What is the force, in billions of Newtons, rounded to the nearest whole number

  • net electric flux

    202057 Net Electric Flux Due to Three Small Charged Spheres The three small spheres shown in the figure (see the attachment) carry charges q1 = 3.80 nC , q2 = -7.65 nC , and q3 = 2.00 nC.

  • electric force between two charges

    The solution computes the electric force between two charges by Coulomb's law. It also shows how to calculate the initial acceleration of the mass if it is released and allowed to move.

  • Electric Force and Coulomb's Law between Two Point Charges

    145372 Electric Force and Coulomb's Law between Two Point Charges Objects A and B are both positively charged. Both have a mass of 500 g, but A has twice the charge of B.

  • Charges and Forces

    So, in order that to be maximum, q should be infinity. 2) Two small charged objects repel each other with a force F when separated by a distance d.

  • The Magnitude of the Electric Potential

    The charge on the small sphere is q=0.90 nC. The two spheres are concentric and insulated from their surroundings. For the following questions, the origin of our coordinates is the center of the spheres.

View More Related Solutions