energy required to cut through a log

Related BrainMass Solutions

• Branch Cut for Log(1 - 1/z^2)

  Now Log(z) has a branch cut starting at 0, Log(z-1) has one starting at 1 and Log(z+1) has one starting at -1. Once again we see that a single branch cut from -1 to 1 and passing through 0 does the trick.

• Chemical potential as function of height in Earth's gravity

  N while keeping U constant as required in Eq. (1).

• How to Find Branch Cuts for log(f(z))

  Similarly, the branch cut from -1 to infinity for g gets transformed to a branch cut from -1 to 0 for f.

• Internal energy and entropy of a two level system

  you see that the resulting expression for S/N is identical to Eq. (12) A detailed solution is given.

• Ideal gas with vibrational degrees of freedom

  Through this exchange a thermal equilibrium between the various degrees of freedom arises.

• Photoelectric Effect: Photo-tubes.

  This minimum energy required to extract electron from the surface of metal is called work function.

• Material properties question

  Therefore, we can rewrite equation (2) as log t = const + (E/k)/T . (2) Now, if we plot (log t) versus (1/t) we should obtain a straight line whose slope would be E/k, and so from this slope we get the activation energy.

• Energy as function of temperature for Einstein solid

  You can again translate this to an "egg coloring problem" with U eggs and N colors. You need U zeros and N-1 lines to specify a coloring. The total number of states is thus: Omega(U) = (N-1+U)!/[(N-1)! U!]

• Entropy of noninteracting distinguishable oscillators

  = (using (3)) = (A + B) Log(A + B) - (A + B) - A Log(A) + A - B Log(B) + B = (A + B) Log(A + B) - A Log(A) - B Log(B) = A Log(A + B) + B Log(A + B) - A Log(A) - B Log(B) = A Log[(A + B)/A] + B Log[(A + B)/B] (4) Taking the Logarithm