Light Attenuation Under Water
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When the light penetrates through the water in a lake, the light intensity decreases with depth. Light intensity f (x) is given by f (x) = 100*(a)^x
Where x is the depth measured in meters below the lake's surface. For a certain pure and kalr lake, the light intensity 16 of 5.0 meters.
a) Determine the number a
b) Determine the depth that corresponds to an intensity of 2.1
c) Determine the half-constant of f
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Solution Summary
We investigate how the light level decreases underwater with increasing depth.
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a) The light intensity at depth x is given by
f(x) = 100 a^x
for some constant x. We have
f(5.0) = 100 a^5 = 16,
whence a^5 = 16/100 = 0.16
so a = (0.16)^(1/5) = 0.69.
b) We have f(x) = 100 * ...
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