Six Sigma-Reliability Function
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The life of a watch battery is normally distributed with a mean of 1,000 days and a standard deviation of 60 days.
a. what fraction of the batteries is expected to survive beyond 1100 days?
b. what fraction will survive fewer than 880 days?
c. sketch the reliability function
d. what length of warranty is needed so that no more than 10% of the batteries will be expected to fail during the warranty period?
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Solution Summary
This solution answers four six-sigma questions, addressing fractions, reliability functions and length of warranty.
Solution Preview
Mean = 1000 days
Standard Deviation = 60 days
a) P(x>1100) = P(z>(x-mean)/standard deviation) = ...
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