Balancing/Redox
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SeO4)-2+BrO-1-->BrO4)-1+SeO2
How do I balance these atoms?
How do I get the reactant charge and the product charge and the total charge?
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Solution Summary
This solution comprises of a concise step by step illustration of how to balance atoms, and how to determine the reactant charge, product charge and total charge.
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The following is the balanced equation in mass.
BrO- + 3H2O ---> BrO4)-1 + 6H+
We know need to balance it in charge. Always do mass then charge. We see we have -1 charge on the left from the BrO-. There is a -1 charge from the BrO4)-1 and +6 charge from the 6H+ on the right. We add these together to give us a +5 charge on right. So in order to balance the ...
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