Uniform acceleration motion
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Time (s) Position (m)
40.40 8.000
41.40 13.050
42.00 21.000
An object is moving in a straight line with a constant acceleration,its position is measured at three different times, as shown in the table below.
Calculate the magnitude of the acceleration at t=41.40 s
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Solution Summary
For given position data for a uniform accelerating motion on a straight line path, acceleration is estimated.
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For time difference, t1 = 41.40 - 40.40 = 1 sec
displacement (s1) = 13.050 - 8.000 = 5.050 m
For time difference, t2 = 42.00 - 41.40 = 0.20 sec
displacement (s2) = 21.000 - 13.050 = 7.950 m
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